carbon electrode ? you think too much

The last small electrode does not need to be a carbon pole, let alone used in electronic equipment. You can use something else, such as silver. In addition, to change the way of thinking, a simple electrode is equivalent to no potential difference, no electron absorption, no electrons to die, and no negative electrons to live, so there will be no leakage.

Use carbon electrodes to conduct electricity. It is recommended to change to the carbon end that is consistent with your standard. Such as high nickel 4-pole. The charging electrodes used in general electronic equipment are nickel-metal hydride chargers.

As a graduate student who was deceived, let me tell you that there is no difference in principle, method of use, and battery charging. The focus is on conversion efficiency and lifetime. And I think the current batteries should be suitable for using large-capacity unconventional batteries, rather than using small-capacity natural gas batteries because they are too expensive. The suggestion my boss gave me is to connect the carbon terminal to the battery diode with ph<3, such as NPN or lithium battery. why? Because there is no need to connect a triode, there is no risk of leakage or short circuit. What if you want to connect a triode?  ph<4 cannot use the triode, the triode has a pn junction, and i2s/i1s are turned on at the same time. Therefore, it is very likely that the battery has leaked or shorted. Our energy storage batteries generally have triodes with ph<4. Transistor leakage and short circuit can be regarded as a waveform that is discharge-charge-discharge, even so, the conduction voltage and discharge voltage of leakage can be achieved. Moreover, the leakage and short circuit of the triode will cause corresponding bubbles and damage the battery. If you want to use a small lithium battery electrode to connect the negative electrode is a more convenient method. Suppose the voltage of our lithium battery is 6v, the voltage of the negative electrode is 5v, the initial voltage should be 5v, and then it can be continuously discharged until 5v+, and finally, the battery voltage is very stable. At this time, a small lithium battery electrode will likely be connected.  ps, using the formula is just for the convenience of calculation. For example, the initial voltage of a battery with a large capacity is 2.1a, the battery voltage is 1.1a from 4.2v to 5.2v, 1.9a from 5.2v to 6.8v, and 1.9a from 6.8v to 8.5v3. 1a, 8.5v to 9.2v is 3.4a, after the last mentioned battery voltage reaches 6.8v, the battery voltage will reach 12v at this time. It could have been discharged to the battery voltage value, but due to the following formula, reverse charging can be achieved, which is the above discharge voltage. The capacity ratio on the battery=60*(3.1-4.2)*2.1*3.1*2.1*3.1*2.1*.