The solution in the graphite electrode contains a large number of carbon elements, and the solution exists as a gas. When some metal impurities are dissolved in the solution, such as palladium and other iron, chromium, cobalt, and other metal elements, a certain amount of metal ions (commonly known as impurities) exist in the solution. ) will have a good catalytic effect, but the metal ions in the aqueous solution will lose electrons, making it difficult for chemical reactions to occur, and the catalytic effect cannot be achieved. Especially for iron-based electrodes, if only iron-based electrodes are considered in the design, there will be too many impurities in the solution, which will make the effective electrode pore size too large, and it will be difficult to catalyze the conversion of effective heavy metal ions into active compounds. Of course, a similar catalytic reaction can also occur by incorporating the calcium-chromium ions in the graphite electrode into the above-mentioned metal ions.

In the case that the electrode should not contain a considerable amount of ions (metal ions), it has a catalytic effect

Thank you. The contacts are all salt-based base electrodes. There are roughly several types of substances in such electrodes, one is calcium iron boron trisulfide compound, the other is calcium iron sulfate sulfide, and the other is carbon sulfide. So what is certain is that such element electrodes will mainly be trisulfide compounds or calcium sulfate iron sulfides. Such an elemental electrode is easy to adsorb impurities in the solvent to form precipitates, which affects the capacity. Due to the low capacity of calcium sulfate, it is generally necessary to add calcium and manganese substances to bring particles, isn't it?

1. Calcium has fine ionic crystals with high electrical conductivity.

2. There are not many ionic crystals in iron, and the electrode pressure is high.

3. The valence of iron is high, and it is easy to crack into fragments and sink to the bottom.

I think the force is different, and the electrode material is different, so the energy is different, so the electrode reaction must be analyzed to solve the problem specifically, the alloy and the material are different, so I think it is difficult to answer you